-x^2+8x+20=36

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Solution for -x^2+8x+20=36 equation: 



-x^2+8x+20=36

We move all terms to the left:

-x^2+8x+20-(36)=0

We add all the numbers together, and all the variables

-1x^2+8x-16=0

a = -1; b = 8; c = -16;
Δ = b2-4ac
Δ = 82-4·(-1)·(-16)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-8}{-2}=+4$

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